12[x+3]=4[2x+9]+4x

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Solution for 12[x+3]=4[2x+9]+4x equation: 


Simplifying
12[x + 3] = 4[2x + 9] + 4x

Reorder the terms:
12[3 + x] = 4[2x + 9] + 4x
[3 * 12 + x * 12] = 4[2x + 9] + 4x
[36 + 12x] = 4[2x + 9] + 4x

Reorder the terms:
36 + 12x = 4[9 + 2x] + 4x
36 + 12x = [9 * 4 + 2x * 4] + 4x
36 + 12x = [36 + 8x] + 4x

Combine like terms: 8x + 4x = 12x
36 + 12x = 36 + 12x

Add '-36' to each side of the equation.
36 + -36 + 12x = 36 + -36 + 12x

Combine like terms: 36 + -36 = 0
0 + 12x = 36 + -36 + 12x
12x = 36 + -36 + 12x

Combine like terms: 36 + -36 = 0
12x = 0 + 12x
12x = 12x

Add '-12x' to each side of the equation.
12x + -12x = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 12x + -12x

Combine like terms: 12x + -12x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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